Optimal. Leaf size=220 \[ -\frac{a^2 (6 b c-11 a d) (b c-a d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x}}{\sqrt{b c-a d}}\right )}{b^{13/2}}+\frac{a^2 \sqrt{c+d x} (6 b c-11 a d) (b c-a d)}{b^6}+\frac{a^2 (c+d x)^{3/2} (6 b c-11 a d)}{3 b^5}-\frac{(c+d x)^{5/2} \left (-693 a^2 d^2-5 b d x (10 b c-99 a d)+180 a b c d+20 b^2 c^2\right )}{315 b^4 d^2}-\frac{x^3 (c+d x)^{5/2}}{b (a+b x)}+\frac{11 x^2 (c+d x)^{5/2}}{9 b^2} \]
[Out]
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Rubi [A] time = 0.608583, antiderivative size = 220, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.3 \[ -\frac{a^2 (6 b c-11 a d) (b c-a d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x}}{\sqrt{b c-a d}}\right )}{b^{13/2}}+\frac{a^2 \sqrt{c+d x} (6 b c-11 a d) (b c-a d)}{b^6}+\frac{a^2 (c+d x)^{3/2} (6 b c-11 a d)}{3 b^5}-\frac{(c+d x)^{5/2} \left (-693 a^2 d^2-5 b d x (10 b c-99 a d)+180 a b c d+20 b^2 c^2\right )}{315 b^4 d^2}-\frac{x^3 (c+d x)^{5/2}}{b (a+b x)}+\frac{11 x^2 (c+d x)^{5/2}}{9 b^2} \]
Antiderivative was successfully verified.
[In] Int[(x^3*(c + d*x)^(5/2))/(a + b*x)^2,x]
[Out]
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Rubi in Sympy [A] time = 61.1699, size = 218, normalized size = 0.99 \[ - \frac{a^{2} \left (c + d x\right )^{\frac{3}{2}} \left (11 a d - 6 b c\right )}{3 b^{5}} + \frac{a^{2} \sqrt{c + d x} \left (a d - b c\right ) \left (11 a d - 6 b c\right )}{b^{6}} - \frac{a^{2} \left (a d - b c\right )^{\frac{3}{2}} \left (11 a d - 6 b c\right ) \operatorname{atan}{\left (\frac{\sqrt{b} \sqrt{c + d x}}{\sqrt{a d - b c}} \right )}}{b^{\frac{13}{2}}} - \frac{x^{3} \left (c + d x\right )^{\frac{5}{2}}}{b \left (a + b x\right )} + \frac{11 x^{2} \left (c + d x\right )^{\frac{5}{2}}}{9 b^{2}} + \frac{8 \left (c + d x\right )^{\frac{5}{2}} \left (\frac{693 a^{2} d^{2}}{8} - \frac{45 a b c d}{2} - \frac{5 b^{2} c^{2}}{2} - \frac{5 b d x \left (99 a d - 10 b c\right )}{8}\right )}{315 b^{4} d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**3*(d*x+c)**(5/2)/(b*x+a)**2,x)
[Out]
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Mathematica [A] time = 0.418519, size = 223, normalized size = 1.01 \[ \frac{\sqrt{c+d x} \left (3465 a^5 d^4+210 a^4 b d^3 (11 d x-31 c)-21 a^3 b^2 d^2 \left (-153 c^2+214 c d x+22 d^2 x^2\right )+18 a^2 b^3 d \left (-10 c^3+131 c^2 d x+47 c d^2 x^2+11 d^3 x^3\right )-10 a b^4 (c+d x)^3 (2 c+11 d x)+10 b^5 x (c+d x)^3 (7 d x-2 c)\right )}{315 b^6 d^2 (a+b x)}-\frac{a^2 (6 b c-11 a d) (b c-a d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x}}{\sqrt{b c-a d}}\right )}{b^{13/2}} \]
Antiderivative was successfully verified.
[In] Integrate[(x^3*(c + d*x)^(5/2))/(a + b*x)^2,x]
[Out]
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Maple [B] time = 0.028, size = 415, normalized size = 1.9 \[{\frac{2}{9\,{b}^{2}{d}^{2}} \left ( dx+c \right ) ^{{\frac{9}{2}}}}-{\frac{4\,a}{7\,d{b}^{3}} \left ( dx+c \right ) ^{{\frac{7}{2}}}}-{\frac{2\,c}{7\,{b}^{2}{d}^{2}} \left ( dx+c \right ) ^{{\frac{7}{2}}}}+{\frac{6\,{a}^{2}}{5\,{b}^{4}} \left ( dx+c \right ) ^{{\frac{5}{2}}}}-{\frac{8\,{a}^{3}d}{3\,{b}^{5}} \left ( dx+c \right ) ^{{\frac{3}{2}}}}+2\,{\frac{ \left ( dx+c \right ) ^{3/2}{a}^{2}c}{{b}^{4}}}+10\,{\frac{{d}^{2}{a}^{4}\sqrt{dx+c}}{{b}^{6}}}-16\,{\frac{{a}^{3}cd\sqrt{dx+c}}{{b}^{5}}}+6\,{\frac{{a}^{2}{c}^{2}\sqrt{dx+c}}{{b}^{4}}}+{\frac{{d}^{3}{a}^{5}}{{b}^{6} \left ( bdx+ad \right ) }\sqrt{dx+c}}-2\,{\frac{{d}^{2}{a}^{4}\sqrt{dx+c}c}{{b}^{5} \left ( bdx+ad \right ) }}+{\frac{{a}^{3}{c}^{2}d}{{b}^{4} \left ( bdx+ad \right ) }\sqrt{dx+c}}-11\,{\frac{{d}^{3}{a}^{5}}{{b}^{6}\sqrt{ \left ( ad-bc \right ) b}}\arctan \left ({\frac{\sqrt{dx+c}b}{\sqrt{ \left ( ad-bc \right ) b}}} \right ) }+28\,{\frac{{d}^{2}{a}^{4}c}{{b}^{5}\sqrt{ \left ( ad-bc \right ) b}}\arctan \left ({\frac{\sqrt{dx+c}b}{\sqrt{ \left ( ad-bc \right ) b}}} \right ) }-23\,{\frac{{a}^{3}{c}^{2}d}{{b}^{4}\sqrt{ \left ( ad-bc \right ) b}}\arctan \left ({\frac{\sqrt{dx+c}b}{\sqrt{ \left ( ad-bc \right ) b}}} \right ) }+6\,{\frac{{a}^{2}{c}^{3}}{{b}^{3}\sqrt{ \left ( ad-bc \right ) b}}\arctan \left ({\frac{\sqrt{dx+c}b}{\sqrt{ \left ( ad-bc \right ) b}}} \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^3*(d*x+c)^(5/2)/(b*x+a)^2,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d*x + c)^(5/2)*x^3/(b*x + a)^2,x, algorithm="maxima")
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Fricas [A] time = 0.303882, size = 1, normalized size = 0. \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d*x + c)^(5/2)*x^3/(b*x + a)^2,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**3*(d*x+c)**(5/2)/(b*x+a)**2,x)
[Out]
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GIAC/XCAS [A] time = 0.233016, size = 436, normalized size = 1.98 \[ \frac{{\left (6 \, a^{2} b^{3} c^{3} - 23 \, a^{3} b^{2} c^{2} d + 28 \, a^{4} b c d^{2} - 11 \, a^{5} d^{3}\right )} \arctan \left (\frac{\sqrt{d x + c} b}{\sqrt{-b^{2} c + a b d}}\right )}{\sqrt{-b^{2} c + a b d} b^{6}} + \frac{\sqrt{d x + c} a^{3} b^{2} c^{2} d - 2 \, \sqrt{d x + c} a^{4} b c d^{2} + \sqrt{d x + c} a^{5} d^{3}}{{\left ({\left (d x + c\right )} b - b c + a d\right )} b^{6}} + \frac{2 \,{\left (35 \,{\left (d x + c\right )}^{\frac{9}{2}} b^{16} d^{16} - 45 \,{\left (d x + c\right )}^{\frac{7}{2}} b^{16} c d^{16} - 90 \,{\left (d x + c\right )}^{\frac{7}{2}} a b^{15} d^{17} + 189 \,{\left (d x + c\right )}^{\frac{5}{2}} a^{2} b^{14} d^{18} + 315 \,{\left (d x + c\right )}^{\frac{3}{2}} a^{2} b^{14} c d^{18} + 945 \, \sqrt{d x + c} a^{2} b^{14} c^{2} d^{18} - 420 \,{\left (d x + c\right )}^{\frac{3}{2}} a^{3} b^{13} d^{19} - 2520 \, \sqrt{d x + c} a^{3} b^{13} c d^{19} + 1575 \, \sqrt{d x + c} a^{4} b^{12} d^{20}\right )}}{315 \, b^{18} d^{18}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d*x + c)^(5/2)*x^3/(b*x + a)^2,x, algorithm="giac")
[Out]